dashtz69
20+ Year Contributor
- 138
- 0
- Apr 16, 2003
Per gallon? Just thought of this today, and didn't know thanks.
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Originally posted by crankbender
1 gallon = 231 in^3
12^3 in^3= 1728 in^3=1 ft^3
sooooo
46.81*(1/1728)*231=6.25759 pounds/gallon
90% of the members that didn't take alot of math.
Originally posted by 98RedGs
= Just90% of the members that didn't take alot of math.
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Originally posted by crankbender
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what do ya mean?

the ^ (carrot) is used to denote something raised to a power.Originally posted by unlikely hero
It weighs 6lbs a gallon. Trust me I know, I'm a pilot and we have to compute weight and balance every time we fly.
=Jason-
.I love my 89. It makes things so much easier in all this higher math I have to do. I swear I have found so many functions on there that I would have loved to have back in high school so I wouldn't have had to learn anything.Originally posted by crankbender
the ^ (carrot) is used to denote something raised to a power.
for example in^3 means in*in*in which is a cubic inch.
2^3 means 2*2*2 = 8
even the new calculators all use the ^ symbol...speaking of which. What calculators do yall use? I still havn't figured out how to do all the programming on the `89. Nor used all the 10058794837501230q750971 built in functions.
For all the other old mathers out there. I donno when that became the way to write it but we didn't do it that way much back many years ago but EVERYTHING is written that way now. Hell they use that stuff on standardized tests instead of superscripting stuff because it avoids confusion.

Originally posted by out there
on a seperate note, i have an 83+ that i never used many functions. why? i just can't see the point in taking extremely advanced math classes. don't get me wrong, i love learning, but algebra 2 pisses me off (as far as i went in school for math, unless you count chemistry). come on, how can you get a real answer using imaginary numbers??? riddle me that! /rant
Originally posted by out there
yes, i realize that an imaginary number squared is -1, but the whole idea of an imaginary number is stupid. think about it, can you use an imaginary axe to chop down a real tree?

Originally posted by leet
So petroleum derivatives weigh less than water? Seeing as 1 gallon of water weighs 8.34 pounds.
EDIT: NVM I'm retarded. Just remembered that petroleum derivatives float on water.
!!!!!Originally posted by thekellbeast
Wait till you get to Calc 2. Sequences and series will own your ass. It's owning mine.
Oh and
http://pump.net/liquiddata/wdspecgrav.htm
gasoline 53.77 pounds per cubic foot.
7.481 gallons per cubic foot.

Originally posted by crankbender
!!!!!
dashtz69
The most obvious choice would be that the function describes the position of a point. The first derivitive is the instantanious velocity, and the second is the instantanious acceleration. However that curve is not continuous and therefore falls apart (Tan is only usable over an interval that does not contain an asemptope for this analysis). your answer is
-.15708(sin(x)cos(x)^5+25.4648cos(x)^3-6.3662E-14(x-.75)sin(x)(cos(x)^2+.4(repeating)sin(x))/(cos(x)^3)
assuming I am understanding your problem correctly. not sure what you mean by tan^2x....i just assumed it to be a misstype and tan^2(x) which is the same as (sin(x)/cos(x))^2 or tan(x)^2.....was it suppose to be tan(x^2)?
Seriously guys if you don't like integrals and derivitives you will have diffferential equations....
However stick with it engineering is fun as hell and it pays pretty good....