dsm-onster
DSM Wiseman
- 8,592
- 130
- Jul 11, 2004
-
Bloxom,
Virginia
I've started a new thread becasue this discussion was getting way off topic in the original thread.
So what spins a turbine wheel?
Admitting that there are more than one variable in the ideal gas law means that more than one variable can change the energy state of the wheel. The temperature of the gases exiting the cylinder cannot remain the same over time. It continues to decline releasing energy. This raises the pressure in the exhaust manifold and contributes a large amount of the total energy propelling the turbine wheel. See Stirling Engine Info and this Stirling Engine.
The Ideal Gas Law: PV = nRT
P = Pressure
V = Volume
n = number of particles
R = the gas constant
T = Temperature
With a spinning turbocharger, all that is constant is n and R, the number of molecules and the gas constant:
PV/T = nR
T can have as much of a direct effect on PV as n. Lets let the R issues go for the sake of simplicity. Temps change pressure drastically! (Note: a steam engine) However, n is constant here of course. There cannot be more mass before the power stroke than after (although Einstein debates this, we will leave it that there is no measurable loss in mass).
Pressure is defined in part by temperature. Further, it cannot be defined w/ out temperature. Temperature affects pressure as much as the number of molecules or the volume:
P = (nR)/(VT)
The exhaust stroke develops mass flow that blows on the turbine blades turning the wheel, but much more than just the energy from the piston's upstroke is propelling the wheel.
The Law of Conservation of Energy applies here. Where there is an temperature drop, energy is lost. It must be recovered somewhere!
As the temperature drops, the gases expand driving the turbine wheel even harder than simply blowing on it w/ the gases. This directly increases the rotational motion of the blade because, if the temperature of the outside (in the downpite and out the tail pipe) were the same, then a lesser amount of energy would be lost by the hot exhaust gases. This would be like putting the turbo system, including the exhaust, in a 1300* oven.
Energy lost goes somewhere. It just can't become non-existant. So it becomes mechanical energy turning the wheel.
Of course, mass flow spins the turbine wheel. The force driving the mass flow is greatly increased by the expansion proccess of cooling molecules. At least 1/3 of the energy lost in the combustion process is through heat transfer. Much of that is recovered in a turbocharger. That is why a turbo can propel the driveshaft at over twice the horsepower normally realized in an n/a appliation.
These equations I provide stand firm. There is a temperature differential accross the turbo. Therefore, the energy lost (going from the hotter exhaust mani to the cooler downpipe) has to go somewhere.
A turbo functions through an isentropic expansion/compression process:
W = m (H2 - H1) (work output/input of an isentropic turbine)
(H2 - H1) = Cp ( T2 - T1) (change of enthalpy using constant specific heat values)
R ln (P2/P1) = Cp ln (T2/T1) (Constant specific heat, isentropic expansion/compression process)
Cp is the specific heat at a constant pressure of the gas.
R is the Universal gas constant
P2/P1 Is turbine outlet pressure divided by inlet pressure.
T2/T1 is turbine outlet temperature divided by turbine inlet temperature.
W = work
m = mass flow rate
H2 and H1 are Enthalpy values
Sources:
Maximum Boost by Corky Bell
The Garrett website:
Take this test from a Honeywell site
:
http://www.honeywell.com/sites/ts/tt/turbofactsbenifits_IQtest.htm. Pay attention to the answer to question #2.
As well, here are some other reputable sites that mention this:
Boosting Your Knowledge of Turbocharging (Part 1 of a 2 part series)
http://www.mustang50magazine.com/techarticles/17739/
Here's a Google Search.
So what spins a turbine wheel?
Admitting that there are more than one variable in the ideal gas law means that more than one variable can change the energy state of the wheel. The temperature of the gases exiting the cylinder cannot remain the same over time. It continues to decline releasing energy. This raises the pressure in the exhaust manifold and contributes a large amount of the total energy propelling the turbine wheel. See Stirling Engine Info and this Stirling Engine.
The Ideal Gas Law: PV = nRT
P = Pressure
V = Volume
n = number of particles
R = the gas constant
T = Temperature
With a spinning turbocharger, all that is constant is n and R, the number of molecules and the gas constant:
PV/T = nR
T can have as much of a direct effect on PV as n. Lets let the R issues go for the sake of simplicity. Temps change pressure drastically! (Note: a steam engine) However, n is constant here of course. There cannot be more mass before the power stroke than after (although Einstein debates this, we will leave it that there is no measurable loss in mass).
Pressure is defined in part by temperature. Further, it cannot be defined w/ out temperature. Temperature affects pressure as much as the number of molecules or the volume:
P = (nR)/(VT)
The exhaust stroke develops mass flow that blows on the turbine blades turning the wheel, but much more than just the energy from the piston's upstroke is propelling the wheel.
The Law of Conservation of Energy applies here. Where there is an temperature drop, energy is lost. It must be recovered somewhere!
As the temperature drops, the gases expand driving the turbine wheel even harder than simply blowing on it w/ the gases. This directly increases the rotational motion of the blade because, if the temperature of the outside (in the downpite and out the tail pipe) were the same, then a lesser amount of energy would be lost by the hot exhaust gases. This would be like putting the turbo system, including the exhaust, in a 1300* oven.
Energy lost goes somewhere. It just can't become non-existant. So it becomes mechanical energy turning the wheel.
Of course, mass flow spins the turbine wheel. The force driving the mass flow is greatly increased by the expansion proccess of cooling molecules. At least 1/3 of the energy lost in the combustion process is through heat transfer. Much of that is recovered in a turbocharger. That is why a turbo can propel the driveshaft at over twice the horsepower normally realized in an n/a appliation.
These equations I provide stand firm. There is a temperature differential accross the turbo. Therefore, the energy lost (going from the hotter exhaust mani to the cooler downpipe) has to go somewhere.
A turbo functions through an isentropic expansion/compression process:
W = m (H2 - H1) (work output/input of an isentropic turbine)
(H2 - H1) = Cp ( T2 - T1) (change of enthalpy using constant specific heat values)
R ln (P2/P1) = Cp ln (T2/T1) (Constant specific heat, isentropic expansion/compression process)
Cp is the specific heat at a constant pressure of the gas.
R is the Universal gas constant
P2/P1 Is turbine outlet pressure divided by inlet pressure.
T2/T1 is turbine outlet temperature divided by turbine inlet temperature.
W = work
m = mass flow rate
H2 and H1 are Enthalpy values
Sources:
Maximum Boost by Corky Bell
The Garrett website:
A pressure and temperature drop occurs (expansion) across the turbine (7), which harnesses the exhaust gas energy to provide the power necessary to drive the compressor
Take this test from a Honeywell site
:http://www.honeywell.com/sites/ts/tt/turbofactsbenifits_IQtest.htm. Pay attention to the answer to question #2.
As well, here are some other reputable sites that mention this:
Boosting Your Knowledge of Turbocharging (Part 1 of a 2 part series)
http://www.mustang50magazine.com/techarticles/17739/
Here's a Google Search.

The volume of the gases go down becasue the piston travels up the cylinder bore during the exhaust stroke. The turbine housing does not expand. Nor does the exhaust manifold. How can the volume of the gas go up if the space the gas fills does not go up?I do not know the volume of the exhaust manifold. But I doubt it is much larger than 500cc.