Deadly BlaZe
15+ Year Contributor
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- Oct 2, 2004
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Alpharetta,
Georgia
So let's say a turbo is boosting 10 psi, how do you determine how many square inches there are for every 10 lbs??
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hey i was just reading an article on modified mag which talks about that and it is exactly double as pounds
ex: 20psi = 40 sq inches
All of them.My question is if it's 10 lbs per square inch...how many square inches are you applying 10 lbs of force to?
All of them.
When you put a volume of gas at x psi into a vessel half the size, you get twice the pressure. See Boyles law for more info.

hey i was just reading an article on modified mag which talks about that and it is exactly double as pounds
ex: 20psi = 40 sq inches
You are confusing surface area with volume. Square units are two dimensional and used to measure surface area. Cubic units are used to measure 3D volume. When expressing the intake of quanities of air, it is necessary to use the fourth dimension; time. Typical maximum intake volumes for our cars are on the order of 400-500 cubic feet per minute (cfm), but it's assumed that the air consumed is typical atmospheric pressure.So then how many square inches are we forcing 10 lbs into a dsm? I'm assuming there is an answer to that, unless psi is just a measurement and there isn't really a certain amount of square inches that we're forcing 10 lbs upon.
Wret that would make it double right?
10psi + 20 sq inches
Wret that would make it double right?
10psi + 20 sq inches
Stevey i know what i read!!!!!!!!!!!!!!!!!!!!
i can prove it

Double the pressure, half the volume. Anything within the pressurized area receives the pressure in proportion to its surface area (square inches). Yes this means that a small object or small surface is exposed to less force than a large surface.Wret that would make it double right?
10psi + 20 sq inches
Double the pressure, half the volume. Anything within the pressurized area receives the pressure in proportion to its surface area (square inches). Yes this means that a small object or small surface is exposed to less force than a large surface.
When everything is exposed to the same pressure, inside and out, the force has little effect, such as what we experience under atmospheric pressure. That's why we often think of (and refer to) atmospheric pressure as zero. It's when there is a pressure differential that things get interesting. Exposed surface area starts to get a little more meaningful. Think of the tiny, thin tube you use for a boost control gauge. Because of the low surface area, it is not exposed to a great amount of force and can easily handle 30 psi of boost pressure. Now think of how much more robust tubing is required for an intercooler pipe that is 2 or 3 inches in diameter.
Becareful not mix up volume and surface area units or you will confuse people even more.I think the "double the pressure, half the volume" thing would be easier with an example: I'll just use surface area. 100in^2 at 10psi = 200in^2 at 5psi. 10psi is double the pressure, and 100in is half the area. 10psi on 100in^2 would be 200lbs of force and 5psi on 200in^2 would be as well.
10psi on a surface area of 20in^2 would be a total of 200lbs of pressure.
So... Boostnhard, I think what you read, and are trying to say... which was not really related to the original question was: 20psi on 40in^2 = 10psi on 20in^2, which is also wrong. It should be 20psi on 40in^2 = 10psi on 80in^2.