Dumbest things you've heard a DSMer say? :)

[Calan]

There is a line that passes through the origin that divides the region bounded by the parabola ƒ(x)=8x-7x² and the x-axis into two regions of equal area. What is the slope of that line?

Who uses that besides teachers...

Anyone that needs to know the slope of a line that divides a parabolic region.

Duh.

 

[NosLaser]

Anyone that needs to know the slope of a line that divides a parabolic region.

Duh.

Haha! Or anyone that would really like to understand what 'area under the curve' means without simply parroting what they read in Turbo magazine.

 

[Calan]

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*****


Fixed.

 

[Cdc1221]

Some of us do. Anybody ever wonder why most cars on the road, and the parts in most 'domestics' are built in japan? And why so many 'poor' people get to flip burgers all their life? From thinking like that

 

[WES_393]

I'm trying to get my gst to sounds like an srt4..

You mean I'm not the only who has a red palm print on my forehead after that thread?

 

[Bud92gsx]

You mean I'm not the only who has a red palm print on my forehead after that thread?

Mine is red from banging my head on the wall after that.Palm print=FAIL.

 

[isantop]

12*X=300 is how you set up the problem, you just skipped step 1. Just pointing out that Basic algebra is used all the time.



Also 15.9 gallons? Are you sure? Granted I always filled up before the gas light went on and never tested how low my tank could get, I don't think I ever put more than 13ish gallons in it

Definitely 15.9. The light comes one between 1 and 2 gallons left in the tank, so it's possible you simply haven't let it get low enough to see it.

Lol dsms never had a 12 gallon tank

{Here is your statement} {here is the point -> · }

 

[undefined0000]

Its a joke man.

I know. Hence why I didn't reply with some witty remark

 

[Diamond Star Werks]

12*X=300 is how you set up the problem, you just skipped step 1. Just pointing out that Basic algebra is used all the time.



Also 15.9 gallons? Are you sure? Granted I always filled up before the gas light went on and never tested how low my tank could get, I don't think I ever put more than 13ish gallons in it

I've put in a tad over 16. Pretty sure the manual says 16.9.

 

[Diamond Star Werks]

Well this thread is kicking today

 

[undefined0000]

I've put in a tad over 16. Pretty sure the manual says 16.9.

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Right out of my manual.

 

[NosLaser]

Okay, since I am really bored, I am going to solve that problem I posted.

ƒ(x)=8x-7x²

First thing is to sketch what you are dealing with. My drawing there isn't exact, but it's close enough that if you graphed it on a calculator, it would look a bit like that. It would be a parabola which opens downward inscribed through the origin, and also passing through the point (8/7,0)

We can find the intersection points this way:

8x-7x² =0
Factor out an x--> x(8-7x)=0
So we know x at least equals zero, that is our first point
Solve for x--> 8-7x=0
x=8/7

Those are our two points of intersection; (0,0) and (8/7,0)

You also want to find the point at which the unknown slope bisects the graph, and you find that this way:

We know the slope of a line is y=mx

Set your original equation 7x-8x²=mx and solve for x
8x-7x² -mx=0
x(8-7x-m)=0
(8-7x-m)=0
8-m=7x
x=(8-m)/7

And that is how you get the points I have illustrated on the graph

Next, to find the total area of the bound region, you need to integrate the original equation from your first point to your second point.

This is the integral from 0 to (8/7) of 8x-7x²dx, so 4x²-7x^3/3
Since your lower limit is 0, you can just plug in your values for the upper limit of integration--> 4(8/7)²-7(8/7)^3/3
Gives you ≈ 1.7416 square units as total area, but we are interested in half, so .8708 square units

Next you need to integrate the original equation that we combined with the slope at its limits, from 0 to (8-m)/7 of 8x-7x²-mxdx

4x²-7x^3/3-mx²/2

4((8-m)/7)²-7/3((8-m)/7)-m/2((8-m)/7)²

Factor out ((8-m)/7)² and get

((8-m)/7)²[4-7/3((8-m)/7)-m/2]

Simplify: ((8-m)/7)²[4-((8-m)/3)-m/2]

Your lowest common denominator is 6, so apply that to the equation, and you get:
((8-m)/7)²[(24-(16-2m)-3m)/6]

Simplify: ((8-m)/7)²[(8-m)/6]

Set that quation equal to the value you found for half the area of the bound region:

((8-m)/7)²[(8-m)/6]=.8708

Simplify the right side by combining those terms:

(8-m)^3/294 (squared 7, multiplied by 6 to get 294)

(8-m)^3/294=.8708

Multiply by 294--> (8-m)^3=256.0152

Take the cubed root of both sides--> 8-m=6.3497

Solve for m---> m=1.6503 which is the slope of your line. Voila!

 

[Cdc1221]

Everyone loves a good argument

 

[NosLaser]

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*****


fixed. :d

like

 

[Diamond Star Werks]

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Right out of my manual.

That's awd, correct.

 

[undefined0000]

That's awd, correct.

uhm.

 

[Diamond Star Werks]

Fwd holds more than awd.

 

[TSI_93]

Gpa was 4.75.

Thats a really high GPA.... I am just gonna assume that your school does it /5 where as every other school I've heard of or attended did it /4. As in 4.0 was perfect gpa.

 

[WES_393]

As in 4.0 was perfect gpa.

That's how it was always done around here. Makes more sense too with A=4 and F=0. I was kicked out of 3 high schools and still graduated with a 3.7 GPA.

 

[necrotopsy]

Fwd holds more than awd.

not true. The gas tank is in a different place because of the rear end, but the capacity is the same.

 

[Diamond Star Werks]

Thats a really high GPA.... I am just gonna assume that your school does it /5 where as every other school I've heard of or attended did it /4. As in 4.0 was perfect gpa.

Yeah in my last year they did. It a was a private school and they changed according to their curriculum I guess. I started on the 3 point first year then 3rd year the 4 point then last year 5 point. But they said they all really equivalent so basically on a four I would have a 3.75. My older brother got a 3.97/4.

 

[Diamond Star Werks]

not true. The gas tank is in a different place because of the rear end, but the capacity is the same.

Then its 1g and 2g that differ. 16.9 is correct for a 2g.

http://www.mitsu-media.com/showthread.php?t=3356

 

[Dert]

Warm up question for you MJ.

There is a line that passes through the origin that divides the region bounded by the parabola ƒ(x)=8x-7x² and the x-axis into two regions of equal area. What is the slope of that line?

=racecar?

 

[isantop]

Thats a really high GPA.... I am just gonna assume that your school does it /5 where as every other school I've heard of or attended did it /4. As in 4.0 was perfect gpa.

In some schools, Advanced classes weight it to out of 5 while normal classes are out of 4. So, that's probably his weighted GPA.

It's like a bonus grade for taking harder classes.

 

[undefined0000]

In some schools, Advanced classes weight it to out of 5 while normal classes are out of 4. So, that's probably his weighted GPA.

It's like a bonus grade for taking harder classes.

I can vouch for that. I was in Gifted & Talented classes for having an IQ of greater than 130, the classes had a slightly higher possible GPA. The super try hards would complain about their "low" 4.0s.