mattdev
15+ Year Contributor
- 349
- 2
- Jul 15, 2006
-
San Antonio,
Texas
I just installed my LC-1 and made a "custom" gauge for it. All it does is reads the analog output voltage. I have both outputs set to 0-5v (wideband).
I did some math to try to relate the voltage to a/f ratio and wanted to double check it.
0v=7.35 a/f
5v=22.39 a/f
I took the difference in a/f (15.04) and divided it by 5 to get 3. So basically triple the voltage and add 7.35. So the formula is...
3v+7.35=x
v=voltage
x=a/f
Is it that easy? Seems too easy;though doing math while driving isn't.
I just wanted to double check the math so I can learn what voltages mean in a/f and eventually be able to read them w/o translating.
I did some math to try to relate the voltage to a/f ratio and wanted to double check it.
0v=7.35 a/f
5v=22.39 a/f
I took the difference in a/f (15.04) and divided it by 5 to get 3. So basically triple the voltage and add 7.35. So the formula is...
3v+7.35=x
v=voltage
x=a/f
Is it that easy? Seems too easy;though doing math while driving isn't.
I just wanted to double check the math so I can learn what voltages mean in a/f and eventually be able to read them w/o translating.
) so here's a cookie :
